What is (3^2-2^3)+(3^4-4^3)-2^4-5^0 ?

The solution to (3^2-2^3)+(3^4-4^3)-2^4-5^0 is 1

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(3^2-2^3)+(3^4-4^3)-2^4-5^0

(3^{2} - 2^{3}) + (3^{4} - 4^{3}) - 2^{4} - 5^{0}

1

Solution steps

(3^{2} - 2^{3}) + (3^{4} - 4^{3}) - 2^{4} - 5^{0}

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{2} - 2^{3}) : 1

3^{2} - 2^{3}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 2^{3}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 9 - 8

Add and subtract (left to right)

9 - 8 : 1

9 - 8

9 - 8 = 1

= 1

= 1

= 1 + (3^{4} - 4^{3}) - 2^{4} - 5^{0}

Calculate within parentheses

(3^{4} - 4^{3}) : 17

3^{4} - 4^{3}

Calculate exponents

3^{4} : 81

3^{4}

3^{4} = 81

= 81

= 81 - 4^{3}

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= 81 - 64

Add and subtract (left to right)

81 - 64 : 17

81 - 64

81 - 64 = 17

= 17

= 17

= 1 + 17 - 2^{4} - 5^{0}

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= 1 + 17 - 16 - 5^{0}

Calculate exponents

5^{0} : 1

5^{0}

5^{0} = 1

= 1

= 1 + 17 - 16 - 1

Add and subtract (left to right)

1 + 17 - 16 - 1 : 1

1 + 17 - 16 - 1

1 + 17 = 18

= 18 - 16 - 1

18 - 16 = 2

= 2 - 1

2 - 1 = 1

= 1

= 1

(2 \cdot 3^{5})^{2}

\frac{10}{3 ^{5} - 18}

- 12 \times 1^{3}

5 \times (\frac{4}{9} - \frac{1}{6}) - 2

5 (- 1) + 7

What is (3^2-2^3)+(3^4-4^3)-2^4-5^0 ?
The solution to (3^2-2^3)+(3^4-4^3)-2^4-5^0 is 1