What is (0-1+2)/(-4-1-2) ?

The solution to (0-1+2)/(-4-1-2) is -1/7

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(0-1+2)/(-4-1-2)

\frac{0 - 1 + 2}{- 4 - 1 - 2}

- \frac{1}{7}

Solution steps

\frac{0 - 1 + 2}{- 4 - 1 - 2}

Solve

0 - 1 + 2 : 1

Follow the PEMDAS order of operations

Add and subtract (left to right)

0 - 1 = - 1

= - 1 + 2

- 1 + 2 = 1

= 1

Solve

- 4 - 1 - 2 : - 7

Follow the PEMDAS order of operations

Add and subtract (left to right)

- 4 - 1 = - 5

= - 5 - 2

- 5 - 2 = - 7

= - 7

= \frac{1}{- 7}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1}{7}

(- 1)^{2} - 2 (1) + 1

\frac{5}{9} (45 - 32)

6 - 2 (- 1)

[2 + (4 \div 2)] \times 4^{2} - 5

1 - 3 (2)^{2}