What is (-4)^3\div 2-3\times 2^3+5(-3)-20 ?

The solution to (-4)^3\div 2-3\times 2^3+5(-3)-20 is -91

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(-4)^3\div 2-3\times 2^3+5(-3)-20

(- 4)^{3} \div 2 - 3 \times 2^{3} + 5 (- 3) - 20

- 91

Solution steps

(- 4)^{3} \div 2 - 3 \times 2^{3} + 5 (- 3) - 20

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{3} : - 64

(- 4)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 4)^{3} = - 4^{3} = - 64

= - 64

= - 64 \div 2 - 3 \times 2^{3} + 5 (- 3) - 20

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= - 64 \div 2 - 3 \times 8 + 5 (- 3) - 20

Multiply and divide (left to right)

- 64 \div 2 : - 32

- 64 \div 2

- 64 \div 2 = - 32

= - 32

= - 32 - 3 \times 8 + 5 (- 3) - 20

Multiply and divide (left to right)

3 \times 8 : 24

3 \times 8

3 \times 8 = 24

= 24

= - 32 - 24 + 5 (- 3) - 20

Multiply and divide (left to right)

5 (- 3) : - 15

5 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 3) = - 5 \cdot 3 = - 15

= - 15

= - 32 - 24 - 15 - 20

Add and subtract (left to right)

- 32 - 24 - 15 - 20 : - 91

- 32 - 24 - 15 - 20

- 32 - 24 = - 56

= - 56 - 15 - 20

- 56 - 15 = - 71

= - 71 - 20

- 71 - 20 = - 91

= - 91

= - 91

(2 \times (4 + 5 - 9)^{3})^{3} \div 7

\frac{5}{2} (2)^{1}

(- (- 3 - 4) - 7)^{3} - 2

6 (- 4) - 5 (- 5)

15 + 8^{2} - (9 + 14)

What is (-4)^3\div 2-3\times 2^3+5(-3)-20 ?
The solution to (-4)^3\div 2-3\times 2^3+5(-3)-20 is -91