What is 2(-2)^2-(-2)-1 ?

The solution to 2(-2)^2-(-2)-1 is 9

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2(-2)^2-(-2)-1

2 (- 2)^{2} - (- 2) - 1

9

Solution steps

2 (- 2)^{2} - (- 2) - 1

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 2 \cdot 4 - (- 2) - 1

Multiply and divide (left to right)

2 \cdot 4 : 8

2 \cdot 4

2 \cdot 4 = 8

= 8

= 8 - (- 2) - 1

Add and subtract (left to right)

8 - (- 2) - 1 : 9

8 - (- 2) - 1

Apply rule

- (- a) = + a

- (- 2) = + 2

= 8 + 2 - 1

8 + 2 = 10

= 10 - 1

10 - 1 = 9

= 9

= 9

1 \cdot 1 0^{2}

(120 \times 30)^{2}

\frac{1}{3} \times 3^{3}

10 \div ((3 - 5) \times (2 - 4) + 10 \div (- 3 - 2))

\frac{99}{- 9 + 5 ^{2}}