What is (-2)^2+2(-2)+2 ?

The solution to (-2)^2+2(-2)+2 is 2

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(-2)^2+2(-2)+2

(- 2)^{2} + 2 (- 2) + 2

2

Solution steps

(- 2)^{2} + 2 (- 2) + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 2 (- 2) + 2

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= 4 - 4 + 2

Add and subtract (left to right)

4 - 4 + 2 : 2

4 - 4 + 2

4 - 4 = 0

= 0 + 2

0 + 2 = 2

= 2

= 2

10 (4) + 4 (1) \times 5 (5)

1 1^{2} + 8^{2}

3 - [- 2 + 1 - (4 - 5 - 7)] - 2 + [- 3 - (5 - 6 - 1) + 2]

1^{3} + 1

3 (2)^{2} + 1