What is (-7)^2\div (-7)+(-3)^2+5^0-1^{20} ?

The solution to (-7)^2\div (-7)+(-3)^2+5^0-1^{20} is 2

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(-7)^2\div (-7)+(-3)^2+5^0-1^{20}

(- 7)^{2} \div (- 7) + (- 3)^{2} + 5^{0} - 1^{20}

2

Solution steps

(- 7)^{2} \div (- 7) + (- 3)^{2} + 5^{0} - 1^{20}

Follow the PEMDAS order of operations

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 49 \div (- 7) + (- 3)^{2} + 5^{0} - 1^{20}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 49 \div (- 7) + 9 + 5^{0} - 1^{20}

Calculate exponents

5^{0} : 1

5^{0}

5^{0} = 1

= 1

= 49 \div (- 7) + 9 + 1 - 1^{20}

Calculate exponents

1^{20} : 1

1^{20}

1^{20} = 1

= 1

= 49 \div (- 7) + 9 + 1 - 1

Multiply and divide (left to right)

49 \div (- 7) : - 7

49 \div (- 7)

Apply rule

a \div (- b) = - a \div b

49 \div (- 7) = - 49 \div 7 = - 7

= - 7

= - 7 + 9 + 1 - 1

Add and subtract (left to right)

- 7 + 9 + 1 - 1 : 2

- 7 + 9 + 1 - 1

- 7 + 9 = 2

= 2 + 1 - 1

2 + 1 = 3

= 3 - 1

3 - 1 = 2

= 2

= 2

(5)^{2} - 4 (5)

(- 2) + (+ 5) + (+ 7) + (- 6)

4^{2} + 1^{2}

(1)^{2} - 2 (1) - 3

6^{2} - 3 \times 4 + 5

What is (-7)^2\div (-7)+(-3)^2+5^0-1^{20} ?
The solution to (-7)^2\div (-7)+(-3)^2+5^0-1^{20} is 2