What is 20-(-45)\div (-3)^2+(-2)\times (-1)^5 ?

The solution to 20-(-45)\div (-3)^2+(-2)\times (-1)^5 is 27

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20-(-45)\div (-3)^2+(-2)\times (-1)^5

20 - (- 45) \div (- 3)^{2} + (- 2) \times (- 1)^{5}

27

Solution steps

20 - (- 45) \div (- 3)^{2} + (- 2) \times (- 1)^{5}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 20 - (- 45) \div 9 + (- 2) \times (- 1)^{5}

Calculate exponents

(- 1)^{5} : - 1

(- 1)^{5}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{5} = - 1^{5} = - 1

= - 1

= 20 - (- 45) \div 9 + (- 2) \times (- 1)

Multiply and divide (left to right)

(- 45) \div 9 : - 5

(- 45) \div 9

Apply rule

(- a) \div b = - a \div b

(- 45) \div 9 = - 45 \div 9 = - 5

= - 5

= 20 - (- 5) + (- 2) \times (- 1)

Multiply and divide (left to right)

(- 2) \times (- 1) : 2

(- 2) \times (- 1)

Apply rule

(- a) \times (- b) = a \times b

(- 2) \times (- 1) = 2 \times 1 = 2

= 2

= 20 - (- 5) + 2

Add and subtract (left to right)

20 - (- 5) + 2 : 27

20 - (- 5) + 2

Apply rule

- (- a) = + a

- (- 5) = + 5

= 20 + 5 + 2

20 + 5 = 25

= 25 + 2

25 + 2 = 27

= 27

= 27

(- 4 + 2)^{2}

27 \times 2 + (32 + 16 \times 4) \times 3

4^{2} - 3^{2} - (2 + 3)

5 (\frac{1}{5} - 5) - 25

3 (1)^{2} - 18 (1) + 24

What is 20-(-45)\div (-3)^2+(-2)\times (-1)^5 ?
The solution to 20-(-45)\div (-3)^2+(-2)\times (-1)^5 is 27