What is (-1)^2+4(-1)-5 ?

The solution to (-1)^2+4(-1)-5 is -8

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(-1)^2+4(-1)-5

(- 1)^{2} + 4 (- 1) - 5

- 8

Solution steps

(- 1)^{2} + 4 (- 1) - 5

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 + 4 (- 1) - 5

Multiply and divide (left to right)

4 (- 1) : - 4

4 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 1) = - 4 \cdot 1 = - 4

= - 4

= 1 - 4 - 5

Add and subtract (left to right)

1 - 4 - 5 : - 8

1 - 4 - 5

1 - 4 = - 3

= - 3 - 5

- 3 - 5 = - 8

= - 8

= - 8

- 9 + 12 + 5 + 3 - 12 - 8 + 6 + 3

(0 + 2)^{2}

8 (3 - 6) - 9 (6 + 1) - 5

5 + 3 \cdot 2^{3}

(2 - 3)^{3}