What is 8/([2(2+2)]) ?

The solution to 8/([2(2+2)]) is 1

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8/([2(2+2)])

\frac{8}{[ 2 ( 2 + 2 ) ]}

1

Solution steps

\frac{8}{[ 2 ( 2 + 2 ) ]}

Solve

[2 (2 + 2)] : 8

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 2) : 4

2 + 2

2 + 2 = 4

= 4

= 2 \cdot 4

Multiply and divide (left to right)

2 \cdot 4 : 8

2 \cdot 4

2 \cdot 4 = 8

= 8

= 8

= \frac{8}{8}

Apply rule

\frac{a}{a} = 1

= 1

1 5^{2} + 8^{2}

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1 0^{1} + 1 0^{0}

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