What is 1/2*(-40)-7 ?

The solution to 1/2*(-40)-7 is -27

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1/2*(-40)-7

\frac{1}{2} \cdot (- 40) - 7

- 27

Solution steps

\frac{1}{2} (- 40) - 7

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{1}{2} (- 40) : - 20

\frac{1}{2} (- 40)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{2} (- 40) = - \frac{1}{2} \cdot 40

Convert element to fraction:

40 = \frac{40}{1}

= - \frac{1}{2} \cdot \frac{40}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{1}{2} \cdot \frac{40}{1} = \frac{1 \cdot 40}{2 \cdot 1}

= - \frac{1 \cdot 40}{2 \cdot 1}

\frac{1 \cdot 40}{2 \cdot 1} = 20

\frac{1 \cdot 40}{2 \cdot 1}

\frac{1 \cdot 40}{2 \cdot 1} = \frac{40}{2}

\frac{1 \cdot 40}{2 \cdot 1}

Multiply the numbers:

1 \cdot 40 = 40

= \frac{40}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{40}{2}

= \frac{40}{2}

Divide the numbers:

\frac{40}{2} = 20

= 20

= - 20

= - 20 - 7

Add and subtract (left to right)

- 20 - 7 : - 27

- 20 - 7

- 20 - 7 = - 27

= - 27

= - 27

- 2^{2} + 9

- 11 + [(- 10) - (- 8)]

4 - (- 5 + 2) - 15 \div (- 5) + 4 \times (- 2)

\frac{2}{5} + 2 (\frac{3}{4} - \frac{1}{4}) + 4

15 + 6 \div 4^{2} - 3^{2}