What is 64\div 8+9-(2\times 3+1)\times 2+35 ?

The solution to 64\div 8+9-(2\times 3+1)\times 2+35 is 38

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64\div 8+9-(2\times 3+1)\times 2+35

64 \div 8 + 9 - (2 \times 3 + 1) \times 2 + 35

38

Solution steps

64 \div 8 + 9 - (2 \times 3 + 1) \times 2 + 35

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \times 3 + 1) : 7

2 \times 3 + 1

Multiply and divide (left to right)

2 \times 3 : 6

2 \times 3

2 \times 3 = 6

= 6

= 6 + 1

Add and subtract (left to right)

6 + 1 : 7

6 + 1

6 + 1 = 7

= 7

= 7

= 64 \div 8 + 9 - 7 \times 2 + 35

Multiply and divide (left to right)

64 \div 8 : 8

64 \div 8

64 \div 8 = 8

= 8

= 8 + 9 - 7 \times 2 + 35

Multiply and divide (left to right)

7 \times 2 : 14

7 \times 2

7 \times 2 = 14

= 14

= 8 + 9 - 14 + 35

Add and subtract (left to right)

8 + 9 - 14 + 35 : 38

8 + 9 - 14 + 35

8 + 9 = 17

= 17 - 14 + 35

17 - 14 = 3

= 3 + 35

3 + 35 = 38

= 38

= 38

8^{2} - (1 + 3 \cdot 4^{2})

5 + 3^{2}

\frac{( 8 \cdot 3 ) ^{4}}{2 ^{8}}

8 \div 4 \times 2 + 18

7^{6} + 7^{5} - 7^{4}

What is 64\div 8+9-(2\times 3+1)\times 2+35 ?
The solution to 64\div 8+9-(2\times 3+1)\times 2+35 is 38