What is (-3)^2+5(-3)+9 ?

The solution to (-3)^2+5(-3)+9 is 3

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(-3)^2+5(-3)+9

(- 3)^{2} + 5 (- 3) + 9

3

Solution steps

(- 3)^{2} + 5 (- 3) + 9

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 5 (- 3) + 9

Multiply and divide (left to right)

5 (- 3) : - 15

5 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 3) = - 5 \cdot 3 = - 15

= - 15

= 9 - 15 + 9

Add and subtract (left to right)

9 - 15 + 9 : 3

9 - 15 + 9

9 - 15 = - 6

= - 6 + 9

- 6 + 9 = 3

= 3

= 3

2 \times 2^{2} + 5 \times 3 + 9

2^{31} - 1

- 2^{2} + 3^{2}

3 (- 2) - 5

2^{2} - 6 (2) + 9