What is (-36/3)+(8)(9/4) ?

The solution to (-36/3)+(8)(9/4) is 6

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(-36/3)+(8)(9/4)

(- \frac{36}{3}) + (8) (\frac{9}{4})

6

Solution steps

(- \frac{36}{3}) + (8) (\frac{9}{4})

\frac{36}{3} = 12

Divide the numbers:

\frac{36}{3} = 12

12

= - 12 + 8 \cdot \frac{9}{4}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

8 \cdot \frac{9}{4} : 18

8 \cdot \frac{9}{4}

Convert element to fraction:

8 = \frac{8}{1}

= \frac{8}{1} \cdot \frac{9}{4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{8 \cdot 9}{1 \cdot 4}

Cancel

\frac{8 \cdot 9}{1 \cdot 4} : 18

\frac{8 \cdot 9}{1 \cdot 4}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{8 \cdot 9}{4}

Divide the numbers:

\frac{8}{4} = 2

= 2 \cdot 9

Multiply the numbers:

2 \cdot 9 = 18

= 18

= 18

= - 12 + 18

Add and subtract (left to right)

- 12 + 18 : 6

- 12 + 18

- 12 + 18 = 6

= 6

= 6

(8 + 5) \times \frac{35}{5} + 6

- 6^{2} + 5 (- 6) - 4

- 6^{2} + 5 (- 6) - 5

\frac{( 75 + 5 ^{2} )}{5 ^{2}}

3 (5) - 5