What is 5^0-7^0-(-8^0)^0-9(-6^0) ?

The solution to 5^0-7^0-(-8^0)^0-9(-6^0) is 8

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5^0-7^0-(-8^0)^0-9(-6^0)

5^{0} - 7^{0} - (- 8^{0})^{0} - 9 (- 6^{0})

8

Solution steps

5^{0} - 7^{0} - (- 8^{0})^{0} - 9 (- 6^{0})

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8^{0}) : - 1

- 8^{0}

- 8^{0} = - 1

= - 1

= 5^{0} - 7^{0} - (- 1)^{0} - 9 (- 6^{0})

Calculate within parentheses

(- 6^{0}) : - 1

- 6^{0}

- 6^{0} = - 1

= - 1

= 5^{0} - 7^{0} - (- 1)^{0} - 9 (- 1)

Calculate exponents

5^{0} : 1

5^{0}

5^{0} = 1

= 1

= 1 - 7^{0} - (- 1)^{0} - 9 (- 1)

Calculate exponents

7^{0} : 1

7^{0}

7^{0} = 1

= 1

= 1 - 1 - (- 1)^{0} - 9 (- 1)

Calculate exponents

(- 1)^{0} : 1

(- 1)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{0} = 1^{0} = 1

= 1

= 1 - 1 - 1 - 9 (- 1)

Multiply and divide (left to right)

9 (- 1) : - 9

9 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

9 (- 1) = - 9 \cdot 1 = - 9

= - 9

= 1 - 1 - 1 - (- 9)

Add and subtract (left to right)

1 - 1 - 1 - (- 9) : 8

1 - 1 - 1 - (- 9)

1 - 1 = 0

= 0 - 1 - (- 9)

0 - 1 = - 1

= - 1 - (- 9)

Apply rule

- (- a) = + a

- (- 9) = + 9

= - 1 + 9

- 1 + 9 = 8

= 8

= 8

2 \cdot \frac{1}{10} - 1

(5 + 16) \div 7 - 2

- 2 + 1 + 2

81 - 8^{2}

- 6 + \frac{3}{8} + \frac{- 1}{12} + \frac{8}{3}

What is 5^0-7^0-(-8^0)^0-9(-6^0) ?
The solution to 5^0-7^0-(-8^0)^0-9(-6^0) is 8