What is 8-(-2/3)+7-(-1 1/3)-5 ?

The solution to 8-(-2/3)+7-(-1 1/3)-5 is 12

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8-(-2/3)+7-(-1 1/3)-5

8 - (- \frac{2}{3}) + 7 - (- 1 \frac{1}{3}) - 5

12

Solution steps

8 - (- \frac{2}{3}) + 7 - (- 1 \frac{1}{3}) - 5

Convert mixed numbers to improper fractions:

1 \frac{1}{3} = \frac{4}{3}

1 \frac{1}{3}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

1 \frac{1}{3} = \frac{1 \cdot 3 + 1}{3}

= \frac{4}{3}

= 8 - (- \frac{2}{3}) + 7 - (- \frac{4}{3}) - 5

Follow the PEMDAS order of operations

Add and subtract (left to right)

8 - (- \frac{2}{3}) + 7 - (- \frac{4}{3}) - 5 : 12

8 - (- \frac{2}{3}) + 7 - (- \frac{4}{3}) - 5

Apply rule

- (- a) = + a

- (- \frac{2}{3}) = + \frac{2}{3}

= 8 + \frac{2}{3} + 7 - (- \frac{4}{3}) - 5

8 + \frac{2}{3} = \frac{26}{3}

8 + \frac{2}{3}

Convert element to fraction:

8 = \frac{8 \cdot 3}{3}

= \frac{8 \cdot 3}{3} + \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{8 \cdot 3 + 2}{3}

8 \cdot 3 + 2 = 26

8 \cdot 3 + 2

Multiply the numbers:

8 \cdot 3 = 24

= 24 + 2

Add the numbers:

24 + 2 = 26

= 26

= \frac{26}{3}

= \frac{26}{3} + 7 - (- \frac{4}{3}) - 5

\frac{26}{3} + 7 = \frac{47}{3}

\frac{26}{3} + 7

Convert element to fraction:

7 = \frac{7 \cdot 3}{3}

= \frac{7 \cdot 3}{3} + \frac{26}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 \cdot 3 + 26}{3}

7 \cdot 3 + 26 = 47

7 \cdot 3 + 26

Multiply the numbers:

7 \cdot 3 = 21

= 21 + 26

Add the numbers:

21 + 26 = 47

= 47

= \frac{47}{3}

= \frac{47}{3} - (- \frac{4}{3}) - 5

Apply rule

- (- a) = + a

- (- \frac{4}{3}) = + \frac{4}{3}

= \frac{47}{3} + \frac{4}{3} - 5

\frac{47}{3} + \frac{4}{3} = 17

\frac{47}{3} + \frac{4}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{47 + 4}{3}

Add the numbers:

47 + 4 = 51

= \frac{51}{3}

Divide the numbers:

\frac{51}{3} = 17

= 17

= 17 - 5

17 - 5 = 12

= 12

= 12

2^{2} + 1 0^{2}

(9 - 6)^{2}

(- 9)^{2} + 9 (- 9)

1 - \frac{1}{3} - \frac{1}{4}

4 + (6^{2} \div \frac{1}{4}) \times 3