What is 10\div (-2)+5\times (-3)-8+4\times 22-50 ?

The solution to 10\div (-2)+5\times (-3)-8+4\times 22-50 is 10

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10\div (-2)+5\times (-3)-8+4\times 22-50

10 \div (- 2) + 5 \times (- 3) - 8 + 4 \times 22 - 50

10

Solution steps

10 \div (- 2) + 5 \times (- 3) - 8 + 4 \times 22 - 50

Follow the PEMDAS order of operations

Multiply and divide (left to right)

10 \div (- 2) : - 5

10 \div (- 2)

Apply rule

a \div (- b) = - a \div b

10 \div (- 2) = - 10 \div 2 = - 5

= - 5

= - 5 + 5 \times (- 3) - 8 + 4 \times 22 - 50

Multiply and divide (left to right)

5 \times (- 3) : - 15

5 \times (- 3)

Apply rule

a \times (- b) = - a \times b

5 \times (- 3) = - 5 \times 3 = - 15

= - 15

= - 5 - 15 - 8 + 4 \times 22 - 50

Multiply and divide (left to right)

4 \times 22 : 88

4 \times 22

4 \times 22 = 88

= 88

= - 5 - 15 - 8 + 88 - 50

Add and subtract (left to right)

- 5 - 15 - 8 + 88 - 50 : 10

- 5 - 15 - 8 + 88 - 50

- 5 - 15 = - 20

= - 20 - 8 + 88 - 50

- 20 - 8 = - 28

= - 28 + 88 - 50

- 28 + 88 = 60

= 60 - 50

60 - 50 = 10

= 10

= 10

8^{3} - 1

\frac{4}{5} + 7 - \frac{5}{4}

- 2 (0) + 1

- 2 (0) + 5

- 2 (0) + 8

What is 10\div (-2)+5\times (-3)-8+4\times 22-50 ?
The solution to 10\div (-2)+5\times (-3)-8+4\times 22-50 is 10