What is 2(2)^2+1(2)+(2(4)-4) ?

The solution to 2(2)^2+1(2)+(2(4)-4) is 14

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2(2)^2+1(2)+(2(4)-4)

2 (2)^{2} + 1 (2) + (2 (4) - 4)

14

Solution steps

2 (2)^{2} + 1 \cdot (2) + (2 (4) - 4)

Follow the PEMDAS order of operations

Calculate within parentheses

(2 (4) - 4) : 4

2 (4) - 4

Multiply and divide (left to right)

2 (4) : 8

2 (4)

Apply rule:

(a) = a

(4) = 4

= 2 \cdot 4

Multiply the numbers:

2 \cdot 4 = 8

= 8

= 8 - 4

Add and subtract (left to right)

8 - 4 : 4

8 - 4

8 - 4 = 4

= 4

= 4

= 2 (2)^{2} + 1 \cdot (2) + 4

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 2 \cdot 4 + 1 \cdot (2) + 4

Multiply and divide (left to right)

2 \cdot 4 : 8

2 \cdot 4

2 \cdot 4 = 8

= 8

= 8 + 1 \cdot (2) + 4

Multiply and divide (left to right)

1 \cdot (2) : 2

1 \cdot (2)

Apply rule:

(a) = a

(2) = 2

= 1 \cdot 2

Multiply the numbers:

1 \cdot 2 = 2

= 2

= 8 + 2 + 4

Add and subtract (left to right)

8 + 2 + 4 : 14

8 + 2 + 4

8 + 2 = 10

= 10 + 4

10 + 4 = 14

= 14

= 14

5 (12) + 3

5 \times (- 2) - 2

9 - (16 + 25)

- (2)^{2} + 3 (2) + 2

1 + 4^{3} \div 2^{2} + 5^{1}