What is [2\times (-4)^2]+[4\times (-2)^3]/4 ?

The solution to [2\times (-4)^2]+[4\times (-2)^3]/4 is 24

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[2\times (-4)^2]+[4\times (-2)^3]/4

[2 \times (- 4)^{2}] + [4 \times (- 2)^{3}] /4

24

Solution steps

[2 \times (- 4)^{2}] + [4 \times (- 2)^{3}] /4

Follow the PEMDAS order of operations

Calculate within parentheses

[2 \times (- 4)^{2}] : 32

2 \times (- 4)^{2}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 2 \times 16

Multiply and divide (left to right)

2 \times 16 : 32

2 \times 16

2 \times 16 = 32

= 32

= 32

= 32 + [4 \times (- 2)^{3}] /4

Calculate within parentheses

[4 \times (- 2)^{3}] : - 32

4 \times (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 4 \times (- 8)

Multiply and divide (left to right)

4 \times (- 8) : - 32

4 \times (- 8)

Apply rule

a \times (- b) = - a \times b

4 \times (- 8) = - 4 \times 8 = - 32

= - 32

= - 32

= 32 - 32/4

Multiply and divide (left to right)

32/4 : 8

32/4

32/4 = 8

= 8

= 32 - 8

Add and subtract (left to right)

32 - 8 : 24

32 - 8

32 - 8 = 24

= 24

= 24

1^{2} + 2^{2} + 3^{2} + 4^{2}

- 2^{2} - 3 (- 2) + 1

3 (- 3) - 2

88 - 4 (7 - 3)^{2} + 2^{3}

9 - 6 - 3

What is [2\times (-4)^2]+[4\times (-2)^3]/4 ?
The solution to [2\times (-4)^2]+[4\times (-2)^3]/4 is 24