What is 35-(8-2)\div 1+(5\div 4)-12\div 6 ?

The solution to 35-(8-2)\div 1+(5\div 4)-12\div 6 is 28 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

35-(8-2)\div 1+(5\div 4)-12\div 6

Solution

35 - (8 - 2) \div 1 + (5 \div 4) - 12 \div 6

Solution

28 \frac{1}{4}

Solution steps

35 - (8 - 2) \div 1 + (5 \div 4) - 12 \div 6

Follow the PEMDAS order of operations

Calculate within parentheses

(8 - 2) : 6

8 - 2

8 - 2 = 6

= 6

= 35 - 6 \div 1 + (5 \div 4) - 12 \div 6

Calculate within parentheses

(5 \div 4) : \frac{5}{4}

5 \div 4

5 \div 4 = \frac{5}{4}

= \frac{5}{4}

= 35 - 6 \div 1 + \frac{5}{4} - 12 \div 6

Multiply and divide (left to right)

6 \div 1 : 6

6 \div 1

6 \div 1 = 6

= 6

= 35 - 6 + \frac{5}{4} - 12 \div 6

Multiply and divide (left to right)

12 \div 6 : 2

12 \div 6

12 \div 6 = 2

= 2

= 35 - 6 + \frac{5}{4} - 2

Add and subtract (left to right)

35 - 6 + \frac{5}{4} - 2 : \frac{113}{4}

35 - 6 + \frac{5}{4} - 2

35 - 6 = 29

= 29 + \frac{5}{4} - 2

29 + \frac{5}{4} = \frac{121}{4}

29 + \frac{5}{4}

Convert element to fraction:

29 = \frac{29 \cdot 4}{4}

= \frac{29 \cdot 4}{4} + \frac{5}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{29 \cdot 4 + 5}{4}

29 \cdot 4 + 5 = 121

29 \cdot 4 + 5

Multiply the numbers:

29 \cdot 4 = 116

= 116 + 5

Add the numbers:

116 + 5 = 121

= 121

= \frac{121}{4}

= \frac{121}{4} - 2

\frac{121}{4} - 2 = \frac{113}{4}

\frac{121}{4} - 2

Convert element to fraction:

2 = \frac{2 \cdot 4}{4}

= - \frac{2 \cdot 4}{4} + \frac{121}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 4 + 121}{4}

- 2 \cdot 4 + 121 = 113

- 2 \cdot 4 + 121

Multiply the numbers:

2 \cdot 4 = 8

= - 8 + 121

Add/Subtract the numbers:

- 8 + 121 = 113

= 113

= \frac{113}{4}

= \frac{113}{4}

= \frac{113}{4}

Convert improper fractions to mixed numbers:

\frac{113}{4} = 28 \frac{1}{4}

\frac{113}{4} = 28

Remainder

1

\frac{113}{4}

Write the problem in long division format

4 \overline{∣ 113}

Divide

11

4

to get

2

Divide

11

4

to get

2

2 4 \overline{∣ 113}

Multiply the quotient digit

(2)

by the divisor

4

2 4 \overline{∣ 113} \underline{8}

Subtract

8

from

11

2 4 \overline{∣ 113} \underline{8} 3

Bring down the next number of the dividend

2 4 \overline{∣ 113} \underline{8} 33

2 4 \overline{∣ 113} \underline{8} 33

Divide

33

4

to get

8

Divide

33

4

to get

8

28 4 \overline{∣ 113} \underline{8} 33

Multiply the quotient digit

(8)

by the divisor

4

28 4 \overline{∣ 113} \underline{8} 33 \underline{32}

Subtract

32

from

33

28 4 \overline{∣ 113} \underline{8} 33 \underline{32} 1

28 4 \overline{∣ 113} \underline{8} 33 \underline{32} 1

The solution for Long Division of

\frac{113}{4}

28

with remainder of

1

28 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{113}{4} = 28 \frac{1}{4}

= 28 \frac{1}{4}

= 28 \frac{1}{4}

Popular Examples

(-25+18-45+12)\div (26-20+46-32)

(- 25 + 18 - 45 + 12) \div (26 - 20 + 46 - 32)

2*10^1

2 \cdot 1 0^{1}

7^2+10^2

7^{2} + 1 0^{2}

-3(-1)+1

- 3 (- 1) + 1

(35\div 5\times 15)\div 7-(5+2^3)

(35 \div 5 \times 15) \div 7 - (5 + 2^{3})

Frequently Asked Questions (FAQ)

What is 35-(8-2)\div 1+(5\div 4)-12\div 6 ?
The solution to 35-(8-2)\div 1+(5\div 4)-12\div 6 is 28 1/4