What is (2\times (-3))(\times (-1)) ?

The solution to (2\times (-3))(\times (-1)) is -6

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(2\times (-3))(\times (-1))

(2 \cdot (- 3)) (\cdot (- 1))

- 6

Solution steps

(2 (- 3)) ((- 1))

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \cdot (- 3)) : - 6

2 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 3) = - 2 \cdot 3 = - 6

= - 6

= - 6 ((- 1))

Multiply and divide (left to right)

- 6 ((- 1)) : - 6

- 6 ((- 1))

Apply rule

- a \cdot (- b) = a \cdot b

- 6 ((- 1)) = 6 \cdot (- 1) = - 6

= - 6

= - 6

- 3 (0) + 1

- 3 (0) + 5

(- 2) - ((- 6) - (- 14)) - ((- 15) + 2)

\frac{- 2}{11} \cdot 3 - \frac{43}{11}

(- 2) - (- 16) + 8 - [(- 14) + (- 1)]

What is (2\times (-3))(\times (-1)) ?
The solution to (2\times (-3))(\times (-1)) is -6