What is 1\times (-4+(-8)) ?

The solution to 1\times (-4+(-8)) is -12

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1\times (-4+(-8))

1 \cdot (- 4 + (- 8))

- 12

Solution steps

1 \cdot (- 4 + (- 8))

Follow the PEMDAS order of operations

Calculate within parentheses

(- 4 + (- 8)) : - 12

- 4 + (- 8)

Add and subtract (left to right)

Apply rule

+ (- a) = - a

+ (- 8) = - 8

= - 4 - 8

- 4 - 8 = - 12

= - 12

= 1 \cdot (- 12)

Multiply and divide (left to right)

1 \cdot (- 12) : - 12

1 \cdot (- 12)

Apply rule

a \cdot (- b) = - a \cdot b

1 \cdot (- 12) = - 1 \cdot 12 = - 12

= - 12

= - 12

45 - 40 \div 8 - 2 \times 20 + (400 \div 100) \times 2

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