What is 12/4*3+18/9*3-4*3 ?

The solution to 12/4*3+18/9*3-4*3 is 3

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12/43+18/93-4*3

\frac{12}{4} \cdot 3 + \frac{18}{9} \cdot 3 - 4 \cdot 3

3

Solution steps

\frac{12}{4} \cdot 3 + \frac{18}{9} \cdot 3 - 4 \cdot 3

\frac{12}{4} = 3

Divide the numbers:

\frac{12}{4} = 3

3

= 3 \cdot 3 + \frac{18}{9} \cdot 3 - 4 \cdot 3

\frac{18}{9} = 2

Divide the numbers:

\frac{18}{9} = 2

2

= 3 \cdot 3 + 2 \cdot 3 - 4 \cdot 3

Follow the PEMDAS order of operations

Multiply and divide (left to right)

3 \cdot 3 : 9

3 \cdot 3

3 \cdot 3 = 9

= 9

= 9 + 2 \cdot 3 - 4 \cdot 3

Multiply and divide (left to right)

2 \cdot 3 : 6

2 \cdot 3

2 \cdot 3 = 6

= 6

= 9 + 6 - 4 \cdot 3

Multiply and divide (left to right)

4 \cdot 3 : 12

4 \cdot 3

4 \cdot 3 = 12

= 12

= 9 + 6 - 12

Add and subtract (left to right)

9 + 6 - 12 : 3

9 + 6 - 12

9 + 6 = 15

= 15 - 12

15 - 12 = 3

= 3

= 3

1 0^{40} mod 210

\frac{360}{4}

(0)^{2} - 4

\frac{1}{0.25}

- 10 - (+ 2) + (- 5) + (+ 4) - (- 20)