What is (-3)^2+6^2\div 2^2+5 ?

The solution to (-3)^2+6^2\div 2^2+5 is 23

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(-3)^2+6^2\div 2^2+5

(- 3)^{2} + 6^{2} \div 2^{2} + 5

23

Solution steps

(- 3)^{2} + 6^{2} \div 2^{2} + 5

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 6^{2} \div 2^{2} + 5

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= 9 + 36 \div 2^{2} + 5

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 9 + 36 \div 4 + 5

Multiply and divide (left to right)

36 \div 4 : 9

36 \div 4

36 \div 4 = 9

= 9

= 9 + 9 + 5

Add and subtract (left to right)

9 + 9 + 5 : 23

9 + 9 + 5

9 + 9 = 18

= 18 + 5

18 + 5 = 23

= 23

= 23

(7 + 3)^{3}

4 - \frac{1}{2} \div 1 \frac{1}{6}

\frac{9 ( 7 - 3 )}{6 + 4 ^{2} - 10}

1 + (- 1)^{1}

- 2 (- 5)^{2}