What is -(-2)^0+3^1+(-4)^2-(-1)^3 ?

The solution to -(-2)^0+3^1+(-4)^2-(-1)^3 is 19

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-(-2)^0+3^1+(-4)^2-(-1)^3

- (- 2)^{0} + 3^{1} + (- 4)^{2} - (- 1)^{3}

19

Solution steps

- (- 2)^{0} + 3^{1} + (- 4)^{2} - (- 1)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{0} : 1

(- 2)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{0} = 2^{0} = 1

= 1

= - 1 + 3^{1} + (- 4)^{2} - (- 1)^{3}

Calculate exponents

3^{1} : 3

3^{1}

3^{1} = 3

= 3

= - 1 + 3 + (- 4)^{2} - (- 1)^{3}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 1 + 3 + 16 - (- 1)^{3}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 1 + 3 + 16 - (- 1)

Add and subtract (left to right)

- 1 + 3 + 16 - (- 1) : 19

- 1 + 3 + 16 - (- 1)

- 1 + 3 = 2

= 2 + 16 - (- 1)

2 + 16 = 18

= 18 - (- 1)

Apply rule

- (- a) = + a

- (- 1) = + 1

= 18 + 1

18 + 1 = 19

= 19

= 19

4 \cdot 1 2^{2}

4 (4 - 1)

20 - 9 + 8 - 7

- 6^{2} + 6 (- 6) + 5

3 0^{2} + 1 8^{2}

What is -(-2)^0+3^1+(-4)^2-(-1)^3 ?
The solution to -(-2)^0+3^1+(-4)^2-(-1)^3 is 19