What is 10^0+6^1+(-3)^2+(-1)^3 ?

The solution to 10^0+6^1+(-3)^2+(-1)^3 is 15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10^0+6^1+(-3)^2+(-1)^3

1 0^{0} + 6^{1} + (- 3)^{2} + (- 1)^{3}

15

Solution steps

1 0^{0} + 6^{1} + (- 3)^{2} + (- 1)^{3}

Follow the PEMDAS order of operations

Calculate exponents

1 0^{0} : 1

1 0^{0}

1 0^{0} = 1

= 1

= 1 + 6^{1} + (- 3)^{2} + (- 1)^{3}

Calculate exponents

6^{1} : 6

6^{1}

6^{1} = 6

= 6

= 1 + 6 + (- 3)^{2} + (- 1)^{3}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 1 + 6 + 9 + (- 1)^{3}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= 1 + 6 + 9 - 1

Add and subtract (left to right)

1 + 6 + 9 - 1 : 15

1 + 6 + 9 - 1

1 + 6 = 7

= 7 + 9 - 1

7 + 9 = 16

= 16 - 1

16 - 1 = 15

= 15

= 15

3/12 + 7/18 + 2/3 - 5/30

(- 5 + 3)^{2} + 8

\frac{3}{4} (1) - 1

2 (3) + 3

12 (6)^{2}