What is 2(2)^2+3(2)(-4)-4(-4)^2 ?

The solution to 2(2)^2+3(2)(-4)-4(-4)^2 is -80

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2(2)^2+3(2)(-4)-4(-4)^2

2 (2)^{2} + 3 (2) (- 4) - 4 (- 4)^{2}

- 80

Solution steps

2 (2)^{2} + 3 (2) (- 4) - 4 (- 4)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 2 \cdot 4 + 3 (2) (- 4) - 4 (- 4)^{2}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 2 \cdot 4 + 3 (2) (- 4) - 4 \cdot 16

Multiply and divide (left to right)

2 \cdot 4 : 8

2 \cdot 4

2 \cdot 4 = 8

= 8

= 8 + 3 (2) (- 4) - 4 \cdot 16

Multiply and divide (left to right)

3 (2) (- 4) : - 24

3 (2) (- 4)

3 (2) = 6

3 (2)

Apply rule:

(a) = a

(2) = 2

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

= 6 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 4) = - 6 \cdot 4 = - 24

= - 24

= 8 - 24 - 4 \cdot 16

Multiply and divide (left to right)

4 \cdot 16 : 64

4 \cdot 16

4 \cdot 16 = 64

= 64

= 8 - 24 - 64

Add and subtract (left to right)

8 - 24 - 64 : - 80

8 - 24 - 64

8 - 24 = - 16

= - 16 - 64

- 16 - 64 = - 80

= - 80

= - 80

50 \cdot 50

2 [\frac{( 8 - 4 ) ^{5}}{8}]

\frac{32}{40}

(2 \cdot 3)^{2} - 5^{2}

3^{2} - (- 3)^{2}

What is 2(2)^2+3(2)(-4)-4(-4)^2 ?
The solution to 2(2)^2+3(2)(-4)-4(-4)^2 is -80