What is (3^2\times 4^2)\times (-1)^5 ?

The solution to (3^2\times 4^2)\times (-1)^5 is -144

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(3^2\times 4^2)\times (-1)^5

(3^{2} \cdot 4^{2}) \cdot (- 1)^{5}

- 144

Solution steps

(3^{2} \cdot 4^{2}) (- 1)^{5}

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{2} \cdot 4^{2}) : 144

3^{2} \cdot 4^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 \cdot 4^{2}

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 9 \cdot 16

Multiply and divide (left to right)

9 \cdot 16 : 144

9 \cdot 16

9 \cdot 16 = 144

= 144

= 144

= 144 (- 1)^{5}

Calculate exponents

(- 1)^{5} : - 1

(- 1)^{5}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{5} = - 1^{5} = - 1

= - 1

= 144 (- 1)

Multiply and divide (left to right)

144 (- 1) : - 144

144 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

144 (- 1) = - 144 \cdot 1 = - 144

= - 144

= - 144

(- 12) - (- 3) + (+ 5)

3^{2} - 2 (3) (4) + 4^{2}

2 (2)^{3} + 3

2 (2)^{3} + 4

7 \cdot 1 0^{2}

What is (3^2\times 4^2)\times (-1)^5 ?
The solution to (3^2\times 4^2)\times (-1)^5 is -144