What is 5\div 3\times (-4\div 7) ?

The solution to 5\div 3\times (-4\div 7) is -20/21

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5\div 3\times (-4\div 7)

5 \div 3 \times (- 4 \div 7)

- \frac{20}{21}

Solution steps

5 \div 3 \times (- 4 \div 7)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 4 \div 7) : \frac{- 4}{7}

- 4 \div 7

- 4 \div 7 = \frac{- 4}{7}

= \frac{- 4}{7}

= 5 \div 3 \times \frac{- 4}{7}

Multiply and divide (left to right)

5 \div 3 \times \frac{- 4}{7} : - \frac{20}{21}

5 \div 3 \times \frac{- 4}{7}

5 \div 3 = \frac{5}{3}

= \frac{5}{3} \times \frac{- 4}{7}

\frac{5}{3} \times \frac{- 4}{7} = - \frac{20}{21}

\frac{5}{3} \cdot \frac{- 4}{7}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 4}{7} = - \frac{4}{7}

= \frac{5}{3} (- \frac{4}{7})

Apply rule:

a (- b) = - ab

\frac{5}{3} (- \frac{4}{7}) = - \frac{5}{3} \cdot \frac{4}{7}

= - \frac{5}{3} \cdot \frac{4}{7}

- \frac{5}{3} \cdot \frac{4}{7} = - \frac{20}{21}

- \frac{5}{3} \cdot \frac{4}{7}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{5}{3} \cdot \frac{4}{7} = \frac{5 \cdot 4}{3 \cdot 7}

= - \frac{5 \cdot 4}{3 \cdot 7}

Multiply the numbers:

5 \cdot 4 = 20

= - \frac{20}{3 \cdot 7}

Multiply the numbers:

3 \cdot 7 = 21

= - \frac{20}{21}

= - \frac{20}{21}

= - \frac{20}{21}

= - \frac{20}{21}

40 \div (4 + 8)

15 - 6 (10 - 1)

2 (4^{2} + 2 + 4)

\frac{3}{4} \times 22 \div 7 \times 9^{2}

- 2 \times (- 2) + 4

What is 5\div 3\times (-4\div 7) ?
The solution to 5\div 3\times (-4\div 7) is -20/21