What is (2^3+3^2+1)/(2^2+5) ?

The solution to (2^3+3^2+1)/(2^2+5) is 2

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(2^3+3^2+1)/(2^2+5)

\frac{2 ^{3} + 3 ^{2} + 1}{2 ^{2} + 5}

2

Solution steps

\frac{2 ^{3} + 3 ^{2} + 1}{2 ^{2} + 5}

Solve

2^{3} + 3^{2} + 1 : 18

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 + 3^{2} + 1

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 8 + 9 + 1

Add and subtract (left to right)

8 + 9 + 1 : 18

8 + 9 + 1

8 + 9 = 17

= 17 + 1

17 + 1 = 18

= 18

= 18

Solve

2^{2} + 5 : 9

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 + 5

Add and subtract (left to right)

4 + 5 : 9

4 + 5

4 + 5 = 9

= 9

= 9

= \frac{18}{9}

Divide the numbers:

\frac{18}{9} = 2

= 2

3^{1} - 4

3^{1} - 1

(1 1^{2} - 11 - 29) \div (11 - 6)

3 \frac{1}{3} - (- 2) \frac{4}{9}

12 - 7 + 3