What is (-2)^3-3(-2)+4 ?

The solution to (-2)^3-3(-2)+4 is 2

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(-2)^3-3(-2)+4

(- 2)^{3} - 3 (- 2) + 4

2

Solution steps

(- 2)^{3} - 3 (- 2) + 4

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 - 3 (- 2) + 4

Multiply and divide (left to right)

3 (- 2) : - 6

3 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 2) = - 3 \cdot 2 = - 6

= - 6

= - 8 - (- 6) + 4

Add and subtract (left to right)

- 8 - (- 6) + 4 : 2

- 8 - (- 6) + 4

Apply rule

- (- a) = + a

- (- 6) = + 6

= - 8 + 6 + 4

- 8 + 6 = - 2

= - 2 + 4

- 2 + 4 = 2

= 2

= 2

(- 2)^{3} - 3 (- 2) + 3

- 7 \times (- 7) \times (- 7)

48 \times 12 \div 5

5 \times 3 - 2

4 (3) + 6