What is 1/2+(4/2+3/6) ?

The solution to 1/2+(4/2+3/6) is 3

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1/2+(4/2+3/6)

\frac{1}{2} + (\frac{4}{2} + \frac{3}{6})

3

Solution steps

\frac{1}{2} + (\frac{4}{2} + \frac{3}{6})

\frac{4}{2} = 2

Divide the numbers:

\frac{4}{2} = 2

2

= \frac{1}{2} + 2 + \frac{3}{6}

\frac{3}{6} = \frac{1}{2}

Cancel the common factor:

3

\frac{1}{2}

= \frac{1}{2} + 2 + \frac{1}{2}

Follow the PEMDAS order of operations

Add and subtract (left to right)

\frac{1}{2} + 2 + \frac{1}{2} : 3

\frac{1}{2} + 2 + \frac{1}{2}

\frac{1}{2} + 2 = \frac{5}{2}

\frac{1}{2} + 2

Convert element to fraction:

2 = \frac{2 \cdot 2}{2}

= \frac{2 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 2 + 1}{2}

2 \cdot 2 + 1 = 5

2 \cdot 2 + 1

Multiply the numbers:

2 \cdot 2 = 4

= 4 + 1

Add the numbers:

4 + 1 = 5

= 5

= \frac{5}{2}

= \frac{5}{2} + \frac{1}{2}

\frac{5}{2} + \frac{1}{2} = 3

\frac{5}{2} + \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 + 1}{2}

Add the numbers:

5 + 1 = 6

= \frac{6}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3

= 3

= 3

3 \cdot 2^{5} - 4 \cdot 2^{4} + 2 \cdot 2^{3} - 1

3^{2} - 3 + 3

2 \div 3 + 1 \div 4 + 5 \div 6

3^{2} - 3 - 6

(- 3) - (- 5) - (- 9)