What is -4+(-8+4)^2+6-3^2+4^3 ?

The solution to -4+(-8+4)^2+6-3^2+4^3 is 73

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-4+(-8+4)^2+6-3^2+4^3

- 4 + (- 8 + 4)^{2} + 6 - 3^{2} + 4^{3}

73

Solution steps

- 4 + (- 8 + 4)^{2} + 6 - 3^{2} + 4^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8 + 4) : - 4

- 8 + 4

- 8 + 4 = - 4

= - 4

= - 4 + (- 4)^{2} + 6 - 3^{2} + 4^{3}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 4 + 16 + 6 - 3^{2} + 4^{3}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 4 + 16 + 6 - 9 + 4^{3}

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= - 4 + 16 + 6 - 9 + 64

Add and subtract (left to right)

- 4 + 16 + 6 - 9 + 64 : 73

- 4 + 16 + 6 - 9 + 64

- 4 + 16 = 12

= 12 + 6 - 9 + 64

12 + 6 = 18

= 18 - 9 + 64

18 - 9 = 9

= 9 + 64

9 + 64 = 73

= 73

= 73

- 12 + (- 27) \div 9 - 4

6 \times (25 - 131)

- (- 1)^{2} - 5 (- 1) + 1

(- 10 + 9 - 8) - (- 7 + 5 - 3)

\frac{2}{5} - (\frac{4}{5} - \frac{8}{15})