What is 7-(-12)\div (-3)+2^2 ?

The solution to 7-(-12)\div (-3)+2^2 is 7

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7-(-12)\div (-3)+2^2

7 - (- 12) \div (- 3) + 2^{2}

7

Solution steps

7 - (- 12) \div (- 3) + 2^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 7 - (- 12) \div (- 3) + 4

Multiply and divide (left to right)

(- 12) \div (- 3) : 4

(- 12) \div (- 3)

Apply rule

(- a) \div (- b) = a \div b

(- 12) \div (- 3) = 12 \div 3 = 4

= 4

= 7 - 4 + 4

Add and subtract (left to right)

7 - 4 + 4 : 7

7 - 4 + 4

7 - 4 = 3

= 3 + 4

3 + 4 = 7

= 7

= 7

(12 - 42 - 52) \times \frac{1}{6}

[- 7 + (- 3) \cdot (- 4)] \cdot [5 - 6 \div (+ 2)] - 11

\frac{10}{5} - \frac{10}{2} (4 - 6)

- 3 - (- 2) + 10

15 - 23 + 12 - (+ 7 - (- 9 + 3) + 9 - 9) + 10