What is 18\div 5-15+2 ?

The solution to 18\div 5-15+2 is -47/5

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18\div 5-15+2

18 \div 5 - 15 + 2

- \frac{47}{5}

Solution steps

18 \div 5 - 15 + 2

Follow the PEMDAS order of operations

Multiply and divide (left to right)

18 \div 5 : \frac{18}{5}

18 \div 5

18 \div 5 = \frac{18}{5}

= \frac{18}{5}

= \frac{18}{5} - 15 + 2

Add and subtract (left to right)

\frac{18}{5} - 15 + 2 : - \frac{47}{5}

\frac{18}{5} - 15 + 2

\frac{18}{5} - 15 = - \frac{57}{5}

\frac{18}{5} - 15

Convert element to fraction:

15 = \frac{15 \cdot 5}{5}

= - \frac{15 \cdot 5}{5} + \frac{18}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 15 \cdot 5 + 18}{5}

- 15 \cdot 5 + 18 = - 57

- 15 \cdot 5 + 18

Multiply the numbers:

15 \cdot 5 = 75

= - 75 + 18

Add/Subtract the numbers:

- 75 + 18 = - 57

= - 57

= \frac{- 57}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{57}{5}

= - \frac{57}{5} + 2

- \frac{57}{5} + 2 = - \frac{47}{5}

- \frac{57}{5} + 2

Convert element to fraction:

2 = \frac{2 \cdot 5}{5}

= \frac{2 \cdot 5}{5} - \frac{57}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 5 - 57}{5}

2 \cdot 5 - 57 = - 47

2 \cdot 5 - 57

Multiply the numbers:

2 \cdot 5 = 10

= 10 - 57

Subtract the numbers:

10 - 57 = - 47

= - 47

= \frac{- 47}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{47}{5}

= - \frac{47}{5}

= - \frac{47}{5}

7 (0) - \frac{9}{8}

1 - \frac{1}{5} + \frac{1}{25} - \frac{1}{125}

(- 1) + (- 2) + (- 3)

- 2 (- 1)^{2} + 6

4 (9 - 3) \div 3 + 2^{3}