What is -3(3)^2+6(3) ?

The solution to -3(3)^2+6(3) is -9

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-3(3)^2+6(3)

- 3 (3)^{2} + 6 (3)

- 9

Solution steps

- 3 (3)^{2} + 6 (3)

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= - 3 \cdot 9 + 6 (3)

Multiply and divide (left to right)

- 3 \cdot 9 : - 27

- 3 \cdot 9

- 3 \cdot 9 = - 27

= - 27

= - 27 + 6 (3)

Multiply and divide (left to right)

6 (3) : 18

6 (3)

Apply rule:

(a) = a

(3) = 3

= 6 \cdot 3

Multiply the numbers:

6 \cdot 3 = 18

= 18

= - 27 + 18

Add and subtract (left to right)

- 27 + 18 : - 9

- 27 + 18

- 27 + 18 = - 9

= - 9

= - 9

2^{0} - 1

20 - 60 + 45

4 + 5 (6 - 4) + 8 \div 2

2 - 2 \times (- 2)

\frac{( - 3 + 6 ) \times ( - 5 + 8 ) + 3 ( - 2 + 5 )}{- 6}