What is (-2-3)^2+(3-3)^2 ?

The solution to (-2-3)^2+(3-3)^2 is 25

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(-2-3)^2+(3-3)^2

(- 2 - 3)^{2} + (3 - 3)^{2}

25

Solution steps

(- 2 - 3)^{2} + (3 - 3)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 - 3) : - 5

- 2 - 3

- 2 - 3 = - 5

= - 5

= (- 5)^{2} + (3 - 3)^{2}

Calculate within parentheses

(3 - 3) : 0

3 - 3

3 - 3 = 0

= 0

= (- 5)^{2} + 0^{2}

Calculate exponents

(- 5)^{2} : 25

(- 5)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2} = 25

= 25

= 25 + 0^{2}

Calculate exponents

0^{2} : 0

0^{2}

0^{2} = 0

= 0

= 25 + 0

Add and subtract (left to right)

25 + 0 : 25

25 + 0

25 + 0 = 25

= 25

= 25

(2 \times 10) - (2 \frac{2}{4}) \times 5

- 2^{2} + 4^{2}

2^{3} + 6

- 2^{2} + 4 (- 2)

\frac{1}{27} + 512 + 81 - \frac{4}{3} + 3375