What is 532+2(4^3-4^2)^2 ?

The solution to 532+2(4^3-4^2)^2 is 5140

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532+2(4^3-4^2)^2

532 + 2 (4^{3} - 4^{2})^{2}

5140

Solution steps

532 + 2 (4^{3} - 4^{2})^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(4^{3} - 4^{2}) : 48

4^{3} - 4^{2}

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= 64 - 4^{2}

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 64 - 16

Add and subtract (left to right)

64 - 16 : 48

64 - 16

64 - 16 = 48

= 48

= 48

= 532 + 2 \cdot 4 8^{2}

Calculate exponents

4 8^{2} : 2304

4 8^{2}

4 8^{2} = 2304

= 2304

= 532 + 2 \cdot 2304

Multiply and divide (left to right)

2 \cdot 2304 : 4608

2 \cdot 2304

2 \cdot 2304 = 4608

= 4608

= 532 + 4608

Add and subtract (left to right)

532 + 4608 : 5140

532 + 4608

532 + 4608 = 5140

= 5140

= 5140

\frac{20}{25}

- (- 2)^{2} + 2

\frac{3.2}{100}

4 [2 - 3 (2 + 4) + 3] - 4 (3 - 4)

\frac{10}{12}