What is 3(-2)^2(3)-2(-2)(3)^2 ?

The solution to 3(-2)^2(3)-2(-2)(3)^2 is 72

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3(-2)^2(3)-2(-2)(3)^2

3 (- 2)^{2} (3) - 2 (- 2) (3)^{2}

72

Solution steps

3 (- 2)^{2} (3) - 2 (- 2) (3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 3 \cdot 4 (3) - 2 (- 2) (3)^{2}

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 3 \cdot 4 (3) - 2 (- 2) \cdot 9

Multiply and divide (left to right)

3 \cdot 4 (3) : 36

3 \cdot 4 (3)

3 \cdot 4 = 12

= 12 (3)

12 (3) = 36

12 (3)

Apply rule:

(a) = a

(3) = 3

= 12 \cdot 3

Multiply the numbers:

12 \cdot 3 = 36

= 36

= 36

= 36 - 2 (- 2) \cdot 9

Multiply and divide (left to right)

2 (- 2) \cdot 9 : - 36

2 (- 2) \cdot 9

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4 \cdot 9

Apply rule

(- a) \cdot b = - a \cdot b

(- 4) \cdot 9 = - 4 \cdot 9 = - 36

= - 36

= 36 - (- 36)

Add and subtract (left to right)

36 - (- 36) : 72

36 - (- 36)

Apply rule

- (- a) = + a

- (- 36) = + 36

= 36 + 36

36 + 36 = 72

= 72

= 72

- 7^{2} + 4 (- 7) - 1

19 + 8 + 12 - 1

6 - 9 - 9

(- 5) - (- 2) - (+ 3) - (- 1)

\frac{0 ^{2} - 25}{0 - 5}