The solution to 3(1-2)^2-7 is -4

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3(1-2)^2-7

Solution

3 (1 - 2)^{2} - 7

- 4

Solution steps

3 (1 - 2)^{2} - 7

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - 2) : - 1

1 - 2

1 - 2 = - 1

= - 1

= 3 (- 1)^{2} - 7

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 3 \cdot 1 - 7

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 - 7

Add and subtract (left to right)

3 - 7 : - 4

3 - 7

3 - 7 = - 4

= - 4

= - 4

2 (- 3)^{2} + 4 (- 3) + 1

3^{3} + (15 + 5) + (11 \times 2)

- 3 (2) + 5

- 2 (- 2)^{3}

1 0^{2} + 2^{2}