What is 3^2+7(2+3)-1 ?

The solution to 3^2+7(2+3)-1 is 43

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3^2+7(2+3)-1

3^{2} + 7 (2 + 3) - 1

43

Solution steps

3^{2} + 7 (2 + 3) - 1

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 3) : 5

2 + 3

2 + 3 = 5

= 5

= 3^{2} + 7 \cdot 5 - 1

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 + 7 \cdot 5 - 1

Multiply and divide (left to right)

7 \cdot 5 : 35

7 \cdot 5

7 \cdot 5 = 35

= 35

= 9 + 35 - 1

Add and subtract (left to right)

9 + 35 - 1 : 43

9 + 35 - 1

9 + 35 = 44

= 44 - 1

44 - 1 = 43

= 43

= 43

2.25

\frac{0.98}{0.54}

(42 - 33) - (- 7 + 12)

(\frac{1}{3}) 9^{3}

\frac{( 21 - 3 )}{( - 3 ) ^{2}}