What is (-1)^0-2^1+(-3)^2+(-2)^3 ?

The solution to (-1)^0-2^1+(-3)^2+(-2)^3 is 0

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(-1)^0-2^1+(-3)^2+(-2)^3

(- 1)^{0} - 2^{1} + (- 3)^{2} + (- 2)^{3}

0

Solution steps

(- 1)^{0} - 2^{1} + (- 3)^{2} + (- 2)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{0} : 1

(- 1)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{0} = 1^{0} = 1

= 1

= 1 - 2^{1} + (- 3)^{2} + (- 2)^{3}

Calculate exponents

2^{1} : 2

2^{1}

2^{1} = 2

= 2

= 1 - 2 + (- 3)^{2} + (- 2)^{3}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 1 - 2 + 9 + (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 1 - 2 + 9 - 8

Add and subtract (left to right)

1 - 2 + 9 - 8 : 0

1 - 2 + 9 - 8

1 - 2 = - 1

= - 1 + 9 - 8

- 1 + 9 = 8

= 8 - 8

8 - 8 = 0

= 0

= 0

2 (3 + 1) - 7

1 - 2^{3} + 2^{6} - 2^{9} + 2^{12}

20 (2)^{2}

\frac{1}{80} (720 - 160)

6 (2) + 4

What is (-1)^0-2^1+(-3)^2+(-2)^3 ?
The solution to (-1)^0-2^1+(-3)^2+(-2)^3 is 0