What is (4-7)^2-6*7+20 ?

The solution to (4-7)^2-6*7+20 is -13

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(4-7)^2-6*7+20

(4 - 7)^{2} - 6 \cdot 7 + 20

- 13

Solution steps

(4 - 7)^{2} - 6 \cdot 7 + 20

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 7) : - 3

4 - 7

4 - 7 = - 3

= - 3

= (- 3)^{2} - 6 \cdot 7 + 20

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 - 6 \cdot 7 + 20

Multiply and divide (left to right)

6 \cdot 7 : 42

6 \cdot 7

6 \cdot 7 = 42

= 42

= 9 - 42 + 20

Add and subtract (left to right)

9 - 42 + 20 : - 13

9 - 42 + 20

9 - 42 = - 33

= - 33 + 20

- 33 + 20 = - 13

= - 13

= - 13

- 2 - (- 4) - 2

12 - [20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2})]

4 (2)^{2}

2 (- 2)^{3}

5 \cdot 1 0^{3}