What is 3-{2-[1+(4+5)-(6+3)]+1} ?

The solution to 3-{2-[1+(4+5)-(6+3)]+1} is 1

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3-{2-[1+(4+5)-(6+3)]+1}

3 - {2 - [1 + (4 + 5) - (6 + 3)] + 1}

1

Solution steps

3 - {2 - [1 + (4 + 5) - (6 + 3)] + 1}

Follow the PEMDAS order of operations

Calculate within parentheses

{2 - [1 + (4 + 5) - (6 + 3)] + 1} : 2

2 - [1 + (4 + 5) - (6 + 3)] + 1

Calculate within parentheses

[1 + (4 + 5) - (6 + 3)] : 1

1 + (4 + 5) - (6 + 3)

Calculate within parentheses

(4 + 5) : 9

4 + 5

4 + 5 = 9

= 9

= 1 + 9 - (6 + 3)

Calculate within parentheses

(6 + 3) : 9

6 + 3

6 + 3 = 9

= 9

= 1 + 9 - 9

Add and subtract (left to right)

1 + 9 - 9 : 1

1 + 9 - 9

1 + 9 = 10

= 10 - 9

10 - 9 = 1

= 1

= 1

= 2 - 1 + 1

Add and subtract (left to right)

2 - 1 + 1 : 2

2 - 1 + 1

2 - 1 = 1

= 1 + 1

1 + 1 = 2

= 2

= 2

= 3 - 2

Add and subtract (left to right)

3 - 2 : 1

3 - 2

3 - 2 = 1

= 1

= 1

6 \div 2 (1 + 2)

6 \div 2 (2 + 1)

48 \div 2 (9 + 3)

\frac{6}{2 ( 1 + 2 )}

6 \div 2 (1 + 3)