What is the tangent of f(x)=ln(x)log_{2}(x),\at x=2 ?

The tangent of f(x)=ln(x)log_{2}(x),\at x=2 is y=x+ln(2)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=ln(x)log_{2}(x),\at x=2

tangent of

f (x) = ln (x) lo g_{2} (x), at x = 2

y = x + ln (2) - 2

Solution steps

Find the tangent point:

(2, ln (2))

Find the slope of

f (x) = ln (x) lo g_{2} (x) : \frac{df ( x )}{d x} = \frac{2 ln ( x )}{ln ( 2 ) x}

Compute the slope of

f (x) = ln (x) lo g_{2} (x)

x = 2 : m = 1

Find the line with slope m=

1

and passing through

(2, ln (2)) : y = x + ln (2) - 2

y = x + ln (2) - 2

f (x) = \frac{1}{x ^{2}}

f (x) = x^{4}

x^{11} arccot (x)

(2, - 14), (- 3, 0)

y = 3 x + 5

What is the tangent of f(x)=ln(x)log_{2}(x),\at x=2 ?
The tangent of f(x)=ln(x)log_{2}(x),\at x=2 is y=x+ln(2)-2