What is the tangent of y=x^2-3x-10,\at x=5.5 ?

The tangent of y=x^2-3x-10,\at x=5.5 is y=8x-40.25

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tangent of y=x^2-3x-10,\at x=5.5

tangent of

y = x^{2} - 3 x - 10, at x = 5.5

y = 8 x - 40.25

Solution steps

Find the tangent point:

(5.5, 3.75)

Find the slope of

y = x^{2} - 3 x - 10 : \frac{d y}{d x} = 2 x - 3

Compute the slope of

y = x^{2} - 3 x - 10

x = 5.5 : m = 8

Find the line with slope m=

8

and passing through

(5.5, 3.75) : y = 8 x - 40.25

y = 8 x - 40.25

(- 1) (0) (4)

y = e^{x^{2}}

f (x) = - \frac{9}{x}, at x = 6

(10, 6), (- 4, 8)

(- 3, - 33)

What is the tangent of y=x^2-3x-10,\at x=5.5 ?
The tangent of y=x^2-3x-10,\at x=5.5 is y=8x-40.25