What is the derivative of y=ln(3x) ?

The derivative of y=ln(3x) is 1/x

What is the first derivative of y=ln(3x) ?

The first derivative of y=ln(3x) is 1/x

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derivative of

y = ln (3 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (3 x))

Apply the chain rule:

\frac{1}{3 x} \frac{d}{d x} (3 x)

= \frac{1}{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= \frac{1}{3 x} \cdot 3

Simplify

\frac{1}{3 x} \cdot 3 : \frac{1}{x}

= \frac{1}{x}

x^{2} sin (x)

(3, 2), (6, 2)

x^{3} - x y + y^{3} = 1

(17, - 11), (- 14, - 16)

(1, 1)

What is the derivative of y=ln(3x) ?
The derivative of y=ln(3x) is 1/x
What is the first derivative of y=ln(3x) ?
The first derivative of y=ln(3x) is 1/x