What is the tangent of f(x)=x^2,\at x=3 ?

The tangent of f(x)=x^2,\at x=3 is y=6x-9

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tangent of f(x)=x^2,\at x=3

tangent of

f (x) = x^{2}, at x = 3

y = 6 x - 9

Solution steps

Find the tangent point:

(3, 9)

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2}

x = 3 : m = 6

Find the line with slope m=

6

and passing through

(3, 9) : y = 6 x - 9

y = 6 x - 9

m = \frac{1}{2}

y = x^{2} ln (x)

f (x) = x^{2}

f (x) = - \frac{5}{x ^{4}}

x = 8

What is the tangent of f(x)=x^2,\at x=3 ?
The tangent of f(x)=x^2,\at x=3 is y=6x-9