What is the derivative of y=4^x ?

The derivative of y=4^x is ln(2)*2^{2x+1}

What is the first derivative of y=4^x ?

The first derivative of y=4^x is ln(2)*2^{2x+1}

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derivative of

y = 4^{x}

ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{x} ln (4)

Simplify

4^{x} ln (4) : ln (2) \cdot 2^{2 x + 1}

= ln (2) \cdot 2^{2 x + 1}

x = 15

(3, \frac{π}{2})

(- 1, 5), (5, 5)

- \frac{1}{2}

y = cos (x)

What is the derivative of y=4^x ?
The derivative of y=4^x is ln(2)*2^{2x+1}
What is the first derivative of y=4^x ?
The first derivative of y=4^x is ln(2)*2^{2x+1}