What is the derivative of f(x)=(x^2+1)^2 ?

The derivative of f(x)=(x^2+1)^2 is 4x(x^2+1)

What is the first derivative of f(x)=(x^2+1)^2 ?

The first derivative of f(x)=(x^2+1)^2 is 4x(x^2+1)

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derivative of

f (x) = (x^{2} + 1)^{2}

4 x (x^{2} + 1)

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{2})

Apply the chain rule:

2 (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

= 2 (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 2 (x^{2} + 1) \cdot 2 x

Simplify

= 4 x (x^{2} + 1)

x = - 1

x = 4

f (x) = \frac{3}{x ^{2}}

y = 3 x^{2}

(3, - 8), (7, 3)

What is the derivative of f(x)=(x^2+1)^2 ?
The derivative of f(x)=(x^2+1)^2 is 4x(x^2+1)
What is the first derivative of f(x)=(x^2+1)^2 ?
The first derivative of f(x)=(x^2+1)^2 is 4x(x^2+1)