What is the derivative of f(x)=x^2-1 ?

The derivative of f(x)=x^2-1 is 2x

What is the first derivative of f(x)=x^2-1 ?

The first derivative of f(x)=x^2-1 is 2x

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derivative of

f (x) = x^{2} - 1

2 x

Solution steps

\frac{d}{d x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x - 0

Simplify

= 2 x

f (x) = \frac{1}{x ^{3}}

(- 1, 1)

f (x) = 9 x + 5, at x = 7

f (x) = \frac{4}{x ^{2}}

3 x^{2}

What is the derivative of f(x)=x^2-1 ?
The derivative of f(x)=x^2-1 is 2x
What is the first derivative of f(x)=x^2-1 ?
The first derivative of f(x)=x^2-1 is 2x